Pressure-Volume Relationships (Boyle's Law) Explained (Chemistry)

An ideal gas in a flexible piston occupies 4.0 Liters at 1.5 atm of pressure. If the volume is compressed isothermally to 2.0 Liters, what is the new pressure in atm? Enter numeric value.

Direct Answer: Pressure-Volume Relationships (Boyle's Law) is defined by: 3. Boyle's law: P₁V₁ = P₂V₂ ⟹ P₂ = (P₁V₁) / V₂ = (1.5 atm × 4.0 L) / 2.0 L = 3.0 atm.

Detailed Step-by-Step Explanation:

Boyle's law: P₁V₁ = P₂V₂ ⟹ P₂ = (P₁V₁) / V₂ = (1.5 atm × 4.0 L) / 2.0 L = 3.0 atm.