In the Haber process: N₂ + 3 H₂ → 2 NH₃. How many moles of ammonia (NH₃) are formed if 6 moles of H₂ react completely with excess N₂? Enter numeric value.
Direct Answer: Stoichiometry & Limiting Reactants is defined by: 4. Molar ratio is 3 mol H₂ : 2 mol NH₃. 6 moles H₂ · (2 mol NH₃ / 3 mol H₂) = 4 moles of NH₃.
Detailed Step-by-Step Explanation:
Molar ratio is 3 mol H₂ : 2 mol NH₃. 6 moles H₂ · (2 mol NH₃ / 3 mol H₂) = 4 moles of NH₃.