A car accelerates uniformly from rest (v₀ = 0) at 4 m/s² over a straight track distance of 50 meters. What is its final velocity in m/s? Enter numeric value.
Direct Answer: Constant Acceleration Kinematics (v² = v₀² + 2ad) is defined by: 20. v² = v₀² + 2ad ⟹ v² = 0 + 2(4 m/s²)(50 m) = 400 ⟹ v = √400 = 20 m/s.
Detailed Step-by-Step Explanation:
v² = v₀² + 2ad ⟹ v² = 0 + 2(4 m/s²)(50 m) = 400 ⟹ v = √400 = 20 m/s.