A 2 kg ball is dropped from a height of 20 meters above the ground. Neglecting air resistance and using g = 10 m/s², what is its velocity in m/s immediately before hitting the ground? Enter numeric value.
Direct Answer: Mechanical Energy Conservation is defined by: 20. Conservation of mechanical energy: mgh = 0.5 mv² ⟹ v = √(2gh) = √(2 · 10 · 20) = √400 = 20 m/s.
Detailed Step-by-Step Explanation:
Conservation of mechanical energy: mgh = 0.5 mv² ⟹ v = √(2gh) = √(2 · 10 · 20) = √400 = 20 m/s.